A stone thrown down with a speed u takes a time t1 to reach the ground. while another stone thrown upward from the same point with the same speed, takes time t2. the maximum height the second stone reaches from the ground is
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X1=-1/2atpow2-ut
X2=ut-1/2atpow2
X1=0 when t=t1
U=1/2at1
At x2=hmax=h
H=1/2at1t2-1/2at2pow2(a=10)
X2=ut-1/2atpow2
X1=0 when t=t1
U=1/2at1
At x2=hmax=h
H=1/2at1t2-1/2at2pow2(a=10)
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