Question

A stone thrown ipwards with a intial velocity 10m/s. Calculate time taken by stone to reach at its maximum height. Acceleration due to gravity is 10m/s^2​

Answer 1

Answer:

Explanation

initial velocity= 10m/s

final velocity= 0m/s

acceleration= 10m/s^2

time= ?

using first equation of motion

v=u+at

0 = 10 + 10t

-10 = 10t

t= 1sec

Answer 2

GIVEN :-

✒ Initial velocity(u) of the stone = 10 m/s

✒ Final velocity(v) of the stone = 0 m/s   【As the stone stops at the maximum height】

✒ Acceleration due to gravity(g) = -10 m/s² 【It is negative as the stone moves opposite to gravity】

TO CALCULATE :-

The maximum height to which the stone reaches.

SOLUTION :-

We know,

$\displaystyle{\sf{v^2-u^2=2as}}$

• Here, s = height required.

$\displaystyle{\sf{\implies (0)^2-(10)^2=2\times-10\times s}}\\\\\displaystyle{\sf{\implies 0-100=-20s}}\\\\\displaystyle{\sf{\implies -100=-20s}}\\\\\boxed{\displaystyle{\sf{\implies s=5\ m}}}$

∵ So, the stone reaches to a maximum height of 5 m.