a stone thrown upward with a speed u from the top of a tower reaches the ground with a velocity 4u the height of the Tower is
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Initial velocity u = u
Final velocity v = -4u
height of tower =h
acceleration = -g
See further solution in comments below....
Final velocity v = -4u
height of tower =h
acceleration = -g
See further solution in comments below....
Cris01:
Sorry it was incomplete solution
Let me tell further that
from Newtons 3rd law of motion
v^2 =u^2 + 2as
then (4u)^2 = u^2 -2gh
2gh=15u^2
h=15u^2/2g
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