A stone thrown upward with a speed u from the top of a tower reaches the ground with a velocity 4u. The height of the tower is
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7
HEY DEAR ...
S = (v^2 - u^2) / (2a)
H = ((4u)^2 - u^2) / (2g)
= (16u^2 - u^2) /(2g)
= 15u^2 / (2g)
= 15u^2 / g
Height of the tower is 4u^2 / g
HOPE , IT HELPS ...
S = (v^2 - u^2) / (2a)
H = ((4u)^2 - u^2) / (2g)
= (16u^2 - u^2) /(2g)
= 15u^2 / (2g)
= 15u^2 / g
Height of the tower is 4u^2 / g
HOPE , IT HELPS ...
tasmiya0509:
the ans is 15u^2 /2g
Answered by
1
V² = u² + 2as
s = v²-u²/2a
s = 16u²-u²/2g
s = 15u²/2g
if g = 10m/s²
s = 3u²/4
s = v²-u²/2a
s = 16u²-u²/2g
s = 15u²/2g
if g = 10m/s²
s = 3u²/4
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