a stone thrown upward with initial velocity u reaches hight h before coming down show that the time taken to come down
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junaid Ahmed from sugar maths and science education certificate of India
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given that,
s= h
g=10m)s²
at maximum hight u2= 0
by Newton's third law of motion,
V² = u2²+2gs
v² = 0² +2×10×h
v² = 20h
v= 2√5h
by Newton's first law of motion,
v= u+gt
2√5h = 0 + 10t
2√5h/10 = t
h/√5 = t
t = h/√5 second
I hope it helpful for you
please mark it as brainliest answer if you have satisfied
s= h
g=10m)s²
at maximum hight u2= 0
by Newton's third law of motion,
V² = u2²+2gs
v² = 0² +2×10×h
v² = 20h
v= 2√5h
by Newton's first law of motion,
v= u+gt
2√5h = 0 + 10t
2√5h/10 = t
h/√5 = t
t = h/√5 second
I hope it helpful for you
please mark it as brainliest answer if you have satisfied
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