Question

a stone thrown upwards at a maximum height of 19.6 M find the velocity with which it was thrown​

Answer 1

Answer:

velocity with which it was thrown is 19.6m/s

Step-by-step explanation:

s=19.6m

v=0 u=?

a=-g=-9.8m/s²

v²-u²=2as

0²-u²=2×-9.8×19.6

-u²=-(19.6×19.6)

u²=19.6×19.6

u=19.6m/s

Answer 2

Answer:

for solving this question we will simply look it in another way.

if it's thrown with initial velocity u and reaches final velocity v (v=0).

Then we can let v(v=0) as initial and u as final as the distance will be same.

now,

u^2-v^2=2as

0-v^2=-2a*-19.6

v^2=19.6*19.6

v=19.6

Mark this as brainliest!!