Question

A stone thrown upwards attains a maximum height of 39.2 . Find the velocity with which it was thrown g=9.8​

Answer 1

Answer:

hope it will help you.........

Answer 2

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The velocity with which it was thrown is 27.718m/s

Explanation:

we know that V2=U2+2as

where V is the final velocity, U is the initial velocity, a is the acceleration, S is the distance covered by stone.

V=O since its final velocity is zero we are left with only U, a and S

Note:Remember that here acceleration is negative.

O=U?+2*(-9.8)*39.2

U2=-2*-19.8)*39.2

U2=768.32

Rooting both sidea we get

U =27.71m/s.