Question

A stone thrown upwards attains a maximum height of 39.2 m. Find the velocity with which it was thrown.​

Answer 1

Answer:

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• A stone thrown upwards attains a maximum height of 39.2 m. Find the velocity with which it was thrown.

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From the question, we get:

• Height (s)=39.2m
• Final Velocity (v)=0m/s
• Acceleration due to Gravity (a)= -10m/s²

To find: Initial velocity (u)

Now:

From the equation of motion:

v²=u²+2as

Putting the values we get:

=>(0m/s)²=u²+2×(-10m/s²)×39.2m

=>0=u²-2×10×39.2

=>u²= 784

=>u=√784

=>u=28m/s

Hence the velocity from which thw was thrown was 28m/s

Answer 2

Answer:

Explanation:

hope it will help you use this formula