Question

a stone thrown upwards takes 3 second to attain maximum height calculate a)initial velocity of stone. b) the maximum height attained by stone. C) net displacement when it comes back.​

Answer 1

t = 3 sec.

g = 9.8 m/s²

Initial Velocity = u = 0 m/s

Using s = ut + 1/2gt²

⇒ s = 0(3) + 1/2(9.8)(3²)

⇒ s = 1/2(9.8)(9)

⇒ s = 4.9(9)

⇒ s = 44.1

∴ Maximum Height = 44.1 metres

Net Displacement will be 0 metres as stone will come back to its starting position.

Answer 2

Answer:

please mark it as brainlist