a stone thrown upwards with velocity of 20m/s take a value of g= 10m/s² i) calculate the maximum height reached by stone ii) calculate total time of flight stone
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Answer:
let, u = 0 m/s
g = 10 m/s²
using equations of motion
1) 2as = v²-u²
= v²-u²/2a
= v² / 2a
= [20m/s]² / 2[10 m/s²]
= 400 m²/s² / 20 m/s²
= 20 m
2) a = v-u/t
t = v-u /a
but u= 0 m/s
t = v /a
= 20 m/s / 10 m/s²
= 2 s
another method
s = ut +1/2at²
40 m = 1/2[10 m/s²]t²
t² = 20m * 2 / 10 m/s²
t² = 4 s²
t = ²√4s²
t = 2 s
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