Question

A stone thrown vertically up in the hand of thrower at the end of 8s.if g at the place is 9.8m/s².calucate the velocity of throw and the greatest height reached by the stone
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Answer 1

Answer:

okay

Explanation:

v =0 at max height

so ..v = u + at

0= u -9.8(8)

u= 9.8(8) = 78.4 m/s(velocity of throw )

Hmax= u^2 / 2g = 6146/19.6 = 313.6 metres

follow

thnks