Question

a stone thrown vertically upward from a certain height. it cover half of distance covered during the time of flight to last second. find time of flight (in second) of the stone​

Answer 1

Answer:

Let body takes T sec to reach maximum height.

Then v = u - gT

v = 0, at highest point.

T=u/g ………… (1)

Velocity attained by Body in (T - t) sec v = u - g (T -t)

= u-gT + zt = u-g u/g + gt

or v = gt …………. (2)

Distance travelled in last t sec of its ascent

S = (gt)t -1/2 gt2 = 1/2 gt2