Question

A stone thrown vertically upward takes 3sec to attains maximum height find the initial velocity of the stone and maximum height attained by the stone

Answer 1

Explanation:

v=u+at. 0=u-10(3) [v=0,a=-10]. u=30m/s . H max=u^2/2g. H max=45m

Answer 2

Hope this helps!
Remember when the stone reaches maximum height the velocity becomes zero.