Question

A stone thrown vertically upward with a velocity of 40 m/s. (g = 10 m/s2)
1) What is the velocity of the stone when it is 40 m above the ground, while moving upwards?
PLS answer

Answer 1

Answer:

Answer

Initial Velocity u=40

Fianl velocity v=0

Height, s=?

By third equation of motion

v

2

−u

2

=2gs

0−40

2

=−2×10×s

s=

20

160

⇒s=80m/s

Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m

Total Diaplacement =0, Since the initial and final point is same.

Explanation:

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