A stone thrown vertically upward with initial velocity 'u' reaches a height 'h' before coming down. Show that the time taken to go up is same as the time taken to come down.
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initial velocity=u
final velicity=0
acceleration=-9.8
since, v=u+at
therefore time taken = (v-u)/a
=-u/-9.8
=u/9.8
while decending, u=0
v= u while ascending
a=9.8
there fore time taken = (v-u)/a
=v/9.8
=u/9.8 since v=u while assending
therefore time is same
final velicity=0
acceleration=-9.8
since, v=u+at
therefore time taken = (v-u)/a
=-u/-9.8
=u/9.8
while decending, u=0
v= u while ascending
a=9.8
there fore time taken = (v-u)/a
=v/9.8
=u/9.8 since v=u while assending
therefore time is same
sharlin2:
Thanks
plz make it the brainest ans
that's correct, thankyou so much. but i don't how make it brainest ans thanks again
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