Question

a stone thrown vertically upward with initial velocity u reaches a height h before comming down show that the time taken to go up is same as the time taken come down​

Answer 1

Explanation:

We have v = u + at and s = ut + -at² at

..s= (v-at)t + at² + 1at² S= 1 2

S = ut -

2

As the stone moves upward from A → B S = AB = h, t = t₁, a = - g (retardation)

u = u and v=0

h = 0 -

h = 2 -gt₁

As the stone moves downward from B→ A

t = t₂, u = 0, s = h and a = g

1 22 h = -gt/2/2

t² = 1²2

t₁ = t₂