a stone thrown vertically upward with initial velocity you reaches a height 'h' before coming down. show that the time taken to go up is same as the yim
Answers
Hii
full ans in this link https://www.toppr.com/ask/question/a-stone-thrown-vertically-upwards-with-initial-velocity-u-reaches-a-height-h-before-coming/
Type your question...
11th
Physics
Motion in a Straight Line
Problems Based on Free Fall
A stone thrown vertically u...
PHYSICS
A stone thrown vertically upwards with initial velocity u reaches a height
′
h
′
before coming down. Show that the time taken to go up is same as the time taken to come down.
December 27, 2019
avatar
Shweta Honey
Share
Save
ANSWER
(i) When stone throw upward with initial velocity, u
Final velocity at maximum height, v=0
Apply kinematic equation of motion.
v=u+at
t=
a
v−u
=
−g
0−u
Apply kinematic equation of motion.
s=ut+
2
1
at
2
h=u(
g
u
)−
2
1
g(
g
u
)
2
u=
2gh
Time,
t=
g
u
=
g
2gh
t=
g
2h
........(1)
(ii) When stone drop from height h
Apply kinematic equation of motion.
v
2
−u
2
=2gh
v=
2gh
Apply kinematic equation of motion.
v=u+at
t=
a
v−u
=
g
2gh
−0
=
g
2h
.......(2)
From (1 ) and (2) it is proved that the time taken to go up is same as the time taken to come down.