Question

A stone thrown vertically upward with velocity 40m/s. g=10m/s.
What is the velocity of the stone when it is 40 m above the ground, while moving upwards?
(A) 50 m/s
(B) 30 m/s
(C) 20 m/s
DI 20/2 m/s​

Answer 1

Explanation:

Initial Velocity u=40

Fianl velocity v=0

Height, s=?

By third equation of motion

v

2

−u

2

=2gs

0−40

2

=−2×10×s

s=

20

160

⇒s=80m/s

Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m

Total Diaplacement =0, Since the initial and final point is same.

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