Question

A stone thrown vertically upwards form the ground with velocity 40 ms-1. The interval
stone is at a height of 60m above the ground (g = 10 ms
252)
(A) 45
(B) 6s
(C) 8s
(D) 12s​

Answer 1

Answer:

60=ut−

21 gt 2

60=40t−5t

2⇒5t 2 −40t+60=0t 1 +t 2 =540 =8t 1 t2 = 560 =12t 1 =6,t 2 =2Hence, interval of time =t1

−t 2 =6−2=4 s.

Explanation:

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