Question

A stone thrown vertically upwards with a speed of 5 m/s. How much high the stone goes

before back to the earth? A=-9.8m/s2

Answer 1

1.27 m is ur answer the distance teaveled by

Answer 2

Initial Velocity=5m/s
Final velocity= 0
Acceleration=-9.8m/s^2
So height will be,
2as= v^2-u^2
2*-9.8*s=0-25
-19.6s=-25
s = 25/19.6
1.27m