Question

A stone thrown vertically upwards with an initial velocity 10m/s from the top of the tower reaches the ground with velocity 30m/s. The height of the tower is ( given:- g = 10 m/s2)​

Answer 1

Explanation:

Initial Velocity u=40

Fianl velocity v=0

Height, s=?

By third equation of motion

v

2

−u

2

=2gs

0−40

2

=−2×10×s

s=

20

160

⇒s=80m/s

Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m

Total Diaplacement =0, Since the initial and final point is same.