A stone thrown vertically upwards with an initial velocity of 60 m/s. what is the time taken by the stone to reach its maximum height?
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Answer:
t=6 seconds
Explanation:
★M-1(by direct formula)
total time of flight =2u/g
therefore,
time of ascend=u/g
t =60/10
t = 6seconds
★M-2(by Newton's equation of motion)
given: u=60m/s. v=0m/s(at max height v=0)
a=-10m/s^2(-g). t=?
by Newton's 1st equation of motion
v=u+at
0=60-10t
10t=60
t=6seconds
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