Question

a stone thrown vertically upwards with initial celocity u reaches a height h time taken to go up is same as the time taken to come down​

Answer 1

the final velocity at height H v=0

hence ,

v=u-gt

u=gt

t=u/g

the time taken in on trip from ground to height H is t=u/g

the time taken for the entire trip=2u/g

I hope this helps ( ╹▽╹ )