a stone thrown vertically upwards with initial velocity u reaches a height h before coming down.show that the time taken to go up is same as the time taken to come down.(please answer me fast its very important)
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v=u+at
0=u-gt
t=u/g
for come down,
v=u+at
v=0+gt
t =v/g. { initial velocity of stone and velocity when it strike to the ground it will same}
so t=u/g
0=u-gt
t=u/g
for come down,
v=u+at
v=0+gt
t =v/g. { initial velocity of stone and velocity when it strike to the ground it will same}
so t=u/g
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