Question

a stone thrown vertically upwards with initial velocity u reaches a height h before coming down.show that the time taken to go up is same as the time taken to come down.(please answer me fast its very important)

Answer 1

v=u+at

0=u-gt

t=u/g


for come down,

v=u+at

v=0+gt

t =v/g. { initial velocity of stone and velocity when it strike to the ground it will same}

so t=u/g