Question

A stone tied to a thread is hanging from the hook of a spring balance. It is gradually immersed into water contained in a jar. What changes do you expect in the reading of the spring balance? ​

Answer 1

Answer:

When the solid is immersed in water the reading of spring balance decreases due to the upthust acting on solid . When you immerse the cylinder into water its weight will decrease due to the upthrust of the water experienced by the body of the cylinder.

Explanation:

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Answer 2

The spring balance will show apparent decrease in weight of the stone.

Let's see a detailed explanation:

• When the weight of the stone is measured in air, the spring balance shows a particular value.

• Now, when the stone is gradually immersed in a jar containing water, the water will exert an upward buoyant force on the stone.

• The buoyant force value will be:

$F_{B}=V_{in}\times\rho\times g$

Here , V_(in) refers to the volume of stone inside water, $\rho$ is density of water and g is gravity.

• This will be reflected in the spring balance by reduction in apparent weight of the stone.

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