Question

A stone tied to the end of a long string 90 cm whirled in a horizontal circle with a constant speed if the stones makes 15 revolution in 30s what is the magnitude and direction of acceleration of the stone​

Answer 1

Explanation:

Frequency f=

25

14

Hz

Angular velocity ω=2πf=

25

2×14π

rad/s=3.52rad/s

Acceleration is a=ω

2

r=3.52

2

×0.8=9.9m/s

2

The direction is along the radius at every point towards the centre....

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