Physics, asked by srimathisakthi1510, 19 days ago

A stone tied to the end of a string, 80 cm long, is whirled in horizontal circle with a constant speed. If the stone makes 14 revolutions in 22 seconds then acceleration of stone is ​

Answers

Answered by manishanikam9527
0

Thus, the magnitude of centripetal acceleration is 9.91 ms − 2 and its direction is always directed along the string, toward the centre, at all points. A stone tied to the end of a string 80 cm long is whirled in a horizontal circle with a constant speed

Answered by dharniathi
0

Answer:

Frequency f= 14/22Hz

Angular velocity ω =2πf= 2*14π/22 ​rad/s = 3.9983 rad/s

Acceleration is a = ω^2R = 4^2 * 0.8 = 12.8 m/s^2

The direction is along the radius at every point towards the centre

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