Question

A stone tied to the end of a string 80cm Long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolution in 22s , then the acceleration of the stone is

Answer 1

Answer:

if the speed of stone is 14 revolution in 43 seconds so the acceliration will be

14 by 22 multiplied by 80 and divided by speed

Explanation:

Answer 2

Answer:

Acceleration of the stone is 9.91 m/s² and direction along the radius towards the Centre.

Explanation:

r = 80 cm = 0.8 m

f = 14/25 = 0.56

ω = 2πf = 2π ×0.56 = 3.52

$a_{c}$ = rω² = 0.8×(3.52)² = 9.91 m/s²

$a_{c}$ = centripetal acceleration ⇒ along the radius towards the Centre.