Question

a stone tied to the end of a string of 1 metre land is held in a horizontal circle with a constant speed if the stone makes 22 revolutions in 44 second what is the magnitude and the direction of acceleration of the stone​

Answer 1

Answer:

I hope this answer is halpful

Answer 2

Answer:

Acceleration of the stone is π² m/s² and direction along the radius towards the Centre.

Explanation:

r = 1 m

f = 22/44 = 1/2

ω = 2πf = 2π ×1/2 = π

$a_{c}$ = rω² = 1×(π)² = π² m/s²

$a_{c}$ = centripetal acceleration ⇒ along the radius towards the Centre.