Question

A stone tied to the end of a string of 1m long is
whirled in a horizontal circle with a constant
speed. If the stone makes 22 revolution in 44
seconds, what is the magnitude and direction of
acceleration of the stone :-​

Answer 1

Answer:9.87 m/s2

Direction is towards the centre of circular path

Explanation:

See the image for solutions

Answer 2

Answer:

Acceleration of the stone is π² m/s² and direction along the radius towards the Centre.

Explanation:

r = 1 m

f = 22/44 = 1/2

ω = 2πf = 2π ×1/2 = π

$a_{c}$ = rω² = 1×(π)² = π² m/s²

$a_{c}$ = centripetal acceleration ⇒ along the radius towards the Centre.