Question

A stone tied to the end of a string of 1m long is whirled in a horizontal circle with a constant speed. If the stone makes 15 revolutions in 30 s what is the magnitude & direction of acceleration of the stone
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Answer 1

Answer:

x2 ms^-2

Explanation:

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Answer 2

Answer:

Acceleration of the stone is π² m/s² and direction along the radius towards the Centre.

Explanation:

r = 1 m

f = 15/30 = 1/2

ω = 2πf = 2π ×1/2 = π

$a_{c}$ = rω² = 1×(π)² = π² m/s²

$a_{c}$ = centripetal acceleration ⇒ along the radius towards the Centre.