Question

a stone vertically thrown upwards with an initial velocity 2m/s find the maximum height which it will reach g=10m/s^2​

Answer 1

first, let's do the initialization.

1.initaial velocity- 2m/s____(u)

2.final velocity-0m/s______(v)

3.acceleration due to gravity=(-10m/s²)

4.height=h=???

so,

we know v²-u²=2gh

replacing the values,

0²-2²=2×(-10)×h

so,

0-4=(-20)h

-4=(-20h)

therefore, h=4/20=1/5

converting 1/5 to decimals,

0.2m is the answer.

so, maximum height reached was 0.2m

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