Question

A stone was dropped off a cliff and hit the ground with a speed of 128 f/s. What is the height of the clifr?

Answer 1

ASSALAMUALAIKUM

EXPLANATION:-

Applicable kinematics equation is

v^-u^ =2gh

where,

v=final velocity

u= initial velocity

g= acceleration due to gravity and

h= height of the cliff

then after inserting given values we get,

v^-u^ =2gh

128^-0^=2*10*h

h= 128*128 / 20

after solving this

h= 819.2

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