Question

a stone weighing 0.2kg tied to the end of a string 0.6 m long is it Whirled in a horizontal circle with a speed of 150 rev min-1 calculate the tension in the string
it is jee question plz solve it and keep progress​

Answer 1

Step-by-step explanation:

Mass, m=0.2 kg

Radius, r=1 m

Angular speed, ω=90 rpm

⟹ω=  

60

90

​  

 

⟹ω=1.5 rps

⟹ω=3π rad/s

(a) Angular velocity, ω=3π rad/s

(b) Centripetal acceleration. a=rw  

2

 

⟹a=1×3π×3π

⟹a=9π  

2

 m/s  

2

 

(c) Centripetal Force, F=ma

⟹F=0.2×9π  

2

 

⟹F=1.8π  

2

 N

(d) Tension in string, = Centripetal Force

⟹T=F=1.8π  

2

 N