A stone weighing 0.5 kg tied to a rope of length 0.5 m revolves in vertical plane the tension of the rope at the bottom point of the circle us 45n
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Hey dear,
I assume you want to know speed of the stone at lowest point.
◆ Answer-
v = 6.324 m/s
◆ Explaination-
# Given-
m = 0.5 kg
r = 0.5 m
T = 45 N
# Solution-
[Refer to the figure]
In vertical circular motion, at lowest point-
T - mg = mv^2 / r
45 - 0.5×10 = 0.5v^2 / 0.5
45 - 5 = v^2
40 = v^2
v = √40
v = 6.324 m/s
Therefore, velocity of the string at lowest point is 6.324 m/s.
Hope this helps...
I assume you want to know speed of the stone at lowest point.
◆ Answer-
v = 6.324 m/s
◆ Explaination-
# Given-
m = 0.5 kg
r = 0.5 m
T = 45 N
# Solution-
[Refer to the figure]
In vertical circular motion, at lowest point-
T - mg = mv^2 / r
45 - 0.5×10 = 0.5v^2 / 0.5
45 - 5 = v^2
40 = v^2
v = √40
v = 6.324 m/s
Therefore, velocity of the string at lowest point is 6.324 m/s.
Hope this helps...
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