A stone weighing 1 kg is dropped from rest from a height of 4 m above the ground. When it has free-fallen 1 m its total energy with respect to the ground is
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Answered by
4
Answer:
29.4 joule
Explanation:
the weight of stone is 1 kg,
the height of stone is 4 m,
gravitational acceleration = 9.8 m/s^2
total mgh 1 m below of free fall = ?
therefore, mgh = 1 × 9.8 × 3
= 29.4 joule
Answered by
3
Answer:
40J
Explanation:
Energy is conserved in free-fall situations (no external forces doing work).
Thus, the total energy would be the same at every stage in falling. Whatever total energy body has initially, it will maintain it throughout the course of its motion.
PE = mgh = 1 x 10 x 4 = 40 J
The object begins with 40 J of potential energy and no kinetic energy. The total mechanical energy (KE + PE) is 40 J.
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