Question

A stone weighing 1 kg is whirled in a vertical circle attached at the end of the rope of length 0.5 meter find the tension at lowest,mid and highest position

Answer 1

Answer:

Explanation:

we have given the following date

mass=1 kg

r=0.5  m

g=9.8 m/s2

Let  

T1= tension at first point

T2= tension at second point  

T3 = temsion at highest point  

Then,

T1=m(v1)^2/r−mg  

=mug/u−mg

=0N

T2=m(v2)^2/r+mg  

=m(5ug)/u−mg

=5mg+mg=6mg  

=58.8N

T3=m(v3)^2/r+mg  

=3×9.8  

=29.4N

Answer 2

Answer:

The tension at lowest,mid and highest position

T1= tension at lower point =0N

T2= tension at mid point  = 58.8N

T3 = temsion at highest point  =29.4N

Explanation:

Given are the date

mass=1 kg

r=0.5  m

g=9.8 m/s2

Then,

T1=m(v1)^2/r−mg  

=mug/u−mg

=0N

T2=m(v2)^2/r+mg  

=m(5ug)/u−mg

=5mg+mg=6mg  

=58.8N

T3=m(v3)^2/r+mg  

=3×9.8  

=29.4N