Question

A stone weighing 3 kg and tied to a string is being rotated in a horizontal circle of 120 cm with a velocity of 500 m/s. Find the total force which tries to break the string.​

Answer 1

Answer:

The total force which tries to break the string is 6,25,000 N.

Explanation:

The mass of the stone, m = 3 Kg

The velocity of the stone when it is rotated, v = 500 m/s

The radius of the circular path, r = 120 cm = 1.2 m

The centripetal force acting on the stone,

F = mv² / r

F = (3 × 500²) / 1.2

F = 750000/1.2

F = 6,25,000 N

The total force which tries to break the string will be equal to this centripetal force acting on the stone.

Answer 2

Given:

Weight of the stone = 3kg

Length of the string = 120cm

Velocity = 500 m/s

To Find:

Total force which tries to break the string.​

Solution:

Using the formula of centripetal force -

F = mv² / r

Substituting the values -  

F = (3 × 500²) / 120

= (3 × 250000)/120

 = 750000/120

= 6250

Answer: The total force which tries to break the string is 6250N