Question

a stone weighs 20g in air.15g in water,find the relative density of the stone

Answer 1

Relative density is the ratio of the density of a substance to the density of a standard, usually water for a liquid or solid, and air for a gas.

And, since the volume is constant for the stone.

In this case it is = 20/15 = 1.33

Answer 2

$\mathbb{\pink{\huge{Hello\:Mate!!!}}}$

$<b><u>Answer</u></b>$

$<b>Relative density = 4</b>$

$<b><u>Step-by-step explanation</u></b>$

$<b>According to Archimedes principle, Upthrust = Weight of a liquid displaced</b>$

Upthrust = 20 - 15 = 5

Now, density of the water = $\frac{1g}{cm^3}$

$\frac{1g}{cm^3}$ = $\frac{5g}{x\: cm^3}$

Therefore, volume of water displaced = x = $5cm^3$

It's density = $\frac{Mass}{Volume}$ = $\frac{20g}{5cm^3}$

Density = $\frac{4g}{1cm^3}$

Relative density = $\frac{Density\:of\:solid}{Density\:of\:water}$

Relative density = $\frac{4}{1}$

$<b>Relative density = 4</b>$

Thanks...!