Question

A Stone weighting 3kg falls from the top of a tower 100m high buries itself 2m deep in the sand. the time peneratio is​

Answer 1

Answer:

The velocity of the ball before reaching the ground is given by

v

2

=u

2

+2as

v

2

=2×9.8×100

v=14

10

Distance penetrated before coming to rest =2m

If the retardation experienced while penetrating is a

v

2

=u

2

−2as

v=0

u

2

=2as

a=490m/s

2

retardation

v=u−at

t=

490

14

10

=0.09s