A stone which has a mass of 12 g and a volume of 6 cm3 is gently lowered into 25 cm3 of water in a measuring cylinder. What will be the new reading on the measuring cylinder?
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Given A stone which has a mass of 12 g and a density of 6g / cm3 is gently lowered into 25 cm3 of water in a measuring cylinder. What will be the new reading on the measuring cylinder?
- We need to find the new reading on the measuring cylinder.
- Mass of stone = 12 g
- Density of the stone = 6 g / cm^3
- Volume of liquid in measuring cylinder = 25 cm^3
- So Density = Mass / Volume
- Volume = Mass / Density
- = 12 / 6
- Volume = 2 cm^3
- Therefore increase in volume will be 25 cm^3 + 2 cm^3
- = 27 cm^3
- So the new reading on the measuring cylinder is 27 cm^3
Reference link will be
https://brainly.in/question/16685691
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