Question

A stone whose volume is 76 cm3 is submerged in a liquid whose density is 0.8 g.cm-3. Determine the upthrust acting on the stone.

Answer 1

Answer:

$upthrust = volume \times density \times acceleration \: due \: to \: gravity \\ upthrust = 76 \times 0.8 \times 10 \\ = 608newton$