Question

A stoneis dropped from top of a tower and after 1 second, another stone is dropped 20m below the top.if both the stones reach the ground at the same time, find the height of tower

Answer 1

The A stoneis dropped from top of a tower and after 1 second, another stone is dropped 20m below the top as follow here :-
      s1=12gt2s1=12gt2

     s2=h+12g(t−1)2s2=h+12g(t−1)2

where hh is the height difference in dropping the stones. 

The stones hit the ground at the same time so we can equate s1=s2s1=s2:

     h−gt+12g=0h−gt+12g=0

⇒t=hg+12⇒t=hg+12

Substituting back to get the height of the tower:

     s1=12g(hg+12)2s1=12g(hg+12)2

Using g=10m/s2g=10m/s2 and, to make the calculation simpler, h=35mh=35m, the height of the tower would be 80m
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