Question

A storage battery of emf 8V and internal resistance 0.5ohm is discharged through a parallel combination of to resistor each of resistance 15 ohm. What is the terminal voltage of the battery?​

Answer 1

Answer:

7.5 V

Explanation:

Emf =8V,

Internal resistance r=0.5Ω
R1 = R2 = 15 Ω

Equivalent capacitance of R1 and R2 is
$\frac{1}{R} = \frac{1}{15} + \frac{1}{15}$

$\frac{1}{R} = \frac{2}{15}$

R= 7.5 Ω

now,

emf = I (R+r)
8 = I (7.5+0.5)

8 = I 8
∴ I = 1A

Now,

E= IR+ Ir
E = V + Ir
8 = V + 1x0.5

∴ V= 7.5 volt