Question

A storage room is 6 m long .5 m wide and 3.5 m high. How many tanks of capacity 120 litres each, can it hold?
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Answer 1

Answer:

\huge\mathbb{\underline{SOLUTION:-}}

SOLUTION:−

\begin{gathered}\bold{Given:-}\begin{cases}\sf{Dimension\:of\:room}\\ \sf{l=6m\: ,=5m\:, h=3.5m}\end{cases}\end{gathered}

Given:−{

Dimensionofroom

l=6m,=5m,h=3.5m

How many tanks of capacity 120 litres can it hold .

\boxed{\sf{Volume \:of\: cuboid=l\times b\times h}}

Volumeofcuboid=l×b×h

\bf\underline{\red{According\:to\: Question;-}}

AccordingtoQuestion;−

Now find the volume of room

\begin{gathered}\sf\implies Volume \:of\:room=6m\times 5m\times3.5\\ \\ \sf\implies Volume =30m{}^{2}\times 3.5m\\ \\ \sf\implies Volume =105m{}^{3}\end{gathered}

⟹Volumeofroom=6m×5m×3.5

⟹Volume=30m

2

×3.5m

⟹Volume=105m

3

The volume of room is 105 cubic metre

Covert cubic metre to litre

\boxed{\sf{1m{}^{3}=1000litre}}

1m

3

=1000litre

\begin{gathered}\sf\implies 105m{}^{3}=1000\times 105\\ \\ \sf\implies 105000litre\end{gathered}

⟹105m

3

=1000×105

⟹105000litre

Answer 2

$\bf \: \underline{Given} :$ ↴

$\sf \: The \: dimensions \: of \: the \: room \: are \: given.$

$\begin{gathered}\begin{gathered}\begin{gathered}\tt\: Dimensions \begin{cases} &\sf{Length = 6 m } \\ &\sf{{Breadth = 5 m}}\\ &\sf{{Height = 3.5 m }} \end{cases}\end{gathered}\end{gathered}\end{gathered}$

$\bf \: \underline{To \: find} :$ ↴

$\sf \: How \: many \: tanks \: of \: capacity \: 120 \: litres\:each, can \: it \: hold\: ?$

$\bf \: \underline{ \underline{Solution}} \: :$ ↴

$\underline{ \sf First \: of \: all\: we \: will \: find \: the\: volume \: of \: the \: room.}$

$\boxed{ \red{\sf \: Volume \: of \: cuboid = Length \times Breadth \times Height}}$

$\implies \sf \: 6 \times 5 \times 3.5$

$\implies \sf \: 30 \times 3.5$

$\implies \sf \: 105.0 \: m ^{3}$

$\underline{ \sf \: So, \: the \: volume \: of \: the \: room \: is \: 105 \: cubic \: meter. }$

$\sf \: Now, we \: will \: convert \: the \: cubic \: meter \: into \: litres.$

$\red{\implies \sf \: 1 \: m ^{3} = 1000 \: litres}$

$\implies \sf \: 105.0 \: m ^{3} = 105 \times 1000$

$\implies \sf \: 105.0 \: m ^{3} = 105000 \: litres$

$\sf \: So,$

$\boxed{\sf{\red{Tanks\:it\:can\: hold=\frac{C apacity\:of\:room}{C apacity\:of\:tanks}}}}$

$\sf \: Putting \: the \: values,$

$\sf\implies T anks\: it \:can \:hold=\dfrac{105000}{120}$

$\sf\implies T anks\: it \:can \:hold=\dfrac{10500\!\!\!\not0}{12\!\!\!\not0}$

$\sf\implies T anks\: it \:can \:hold= 875$

$\underline{\boxed{\sf{\pink{Number\:of\: tanks\:it\:can\:hold=875}}}}$