Math, asked by ujmaqureshi0786, 8 months ago

A storage tank at a petrol station is a cuboid 4 m long, 3 m wide and 2 m deep. In one day if
alla 7200 litres of petrol from the tank, what is the fall in the level of the petrol in the tank?

Answers

Answered by knjroopa
83

Step-by-step explanation:

Given  

A storage tank at a petrol station is a cuboid 4 m long, 3 m wide and 2 m deep. In one day if all 7200 litres of petrol from the tank  what is the fall in the level of the petrol in the tank?

  • If all the petrol the petrol of about 7200 litres evaporates
  • Then volume of petrol evaporated will be 7200 x 1000 cm^3
  •                                                                  = 7200000 cm^3
  • Now area of cross section of tank = 400 x 300 cm^3
  •                                                       = 120000 cm^3
  • So fall in the level of petrol tank is 7200000 / 120000
  •                                                               = 60 cm
Answered by isyllus
44

The fall in the level of the petrol in the tank is 0.6 m

Step-by-step explanation:

A storage tank at a petrol station is a cuboid 4 m long, 3 m wide and 2 m deep.

The volume of tank = Length × width × Height

where, length = 4 m , wide = 3 m and deep = 2 m

Volume of tank =4\times 3\times 2

                          =24\ m^3

But  1\ m^3=1000\ liters

In 24 m³ = 24×1000

              = 24000 liters

In petrol tank amount of petrol = 24000 liters

In one day 7200 liters taken out.

Amount of petrol left in tank = 24000 - 7200

                                               = 16800 liters

1000 liters = 1 m³

16800 liters = 16.8 m³

let new height of tank be x m

Volume of tank =4\times 3\times x

12x=16.8

x=1.4\ m

The fall in level of petrol = 2 - 1.4

                                         = 0.6 m

#Learn more:

https://brainly.in/question/12583847

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