Question

A store holds a sale where all merchandise is discounted by 40%. If a shopper buys three items and pays a total (discounted) price of $162, what was the average price of three items before discount was applied?

Answer 1

Answer: 270$

Step-by-step explanation:

• Let the price of each item be x$.

• So, according to question

        $3x-(\frac{40}{100}*3x )=162$

     ⇒3x-(0.4*3x)=162

     ⇒3x-1.2x=162

     ⇒1.8x=162

     ⇒x=$\frac{162}{1.8}$

     ⇒x=$\frac{1620}{18}$

     ∴ x= 90$  

• So,the average price of three items before discount=3×90$

                                                                                                 =270$

Answer 2

Answer:$90

Step-by-step explanation:

To find the average price of the three items before the discount, we can work backwards based on the given information.

Let's assume the average price of the three items before the discount is x.

After applying a 40% discount, the price of each item would be 0.6x (60% of x).

So, the total price of the three items after the discount would be 3 * 0.6x = 1.8x.

Given that the total price after the discount is $162, we can set up the equation:

1.8x = 162

To find x, we can divide both sides of the equation by 1.8:

x = 162 / 1.8 = 90

Therefore, the average price of the three items before the discount was $90.