Question

a store is in the form of a cubiod of dimensions 90 m× 45 m× 30 m . how many cubical boxes of edge 1.5 can be stored in that room ​

Answer 1

Given :-

• Length of the Room = 90m
• Breadth of the Room = 45m
• Height of the Room = 30m

To Find :-

• How many cubical boxes of edge 1.5m can be stored in that room.

Solution :-

➟ Volume of Room = L × B × H

➟ Volume of Room = 90 × 45 × 30

➟ Volume of Room = 4050 × 30

➟ Volume of Room = 121500m³

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➟Boxed stored = Volume/Edge of Cube

➟ Boxed stored = 121500 / 1.5

➟ Boxed stored = 81000 boxes

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So, 81000 boxes can be stored in the Room

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Answer 2

⭐GIVEN DETAILS⭐

*Length of Cuboid = 90 m

*Breadth of Cuboid = 45 m

*Height of Cuboid = 30 m

No. of cubical boxes of edge 1.5 that can be stored in the room =?

Firstly, The Volume of Room = Length * Breadth * Height

                                                = 90 * 45 * 30

                                                = 121500 m³

Boxed stored = Volume/Edge of Cube

                       = 121500/1.5

                       = 81000 Boxes

Hence, 81000 Boxes can be stored in that room.

⚡HOPE IT HELPS UH⚡