Math, asked by CHAKRIKADARI4132, 1 year ago

A store is selling a jacket on sale at 30% off the marked price. A matching pair of pants is on sale at 40% off the marked price. If the marked price of the pants is Rs. 8500 less than the marked price of the jacket and the total sale price of both items is Rs. 23500, then what is the marked price of the jacket?

Answers

Answered by thaoanhbunny06
1

Answer:

Let Market price of jacket = X ₹

so Market price of pants = X- 11600

so according to Question  

X × 70/100 + ( X-11600)× 50/100 = 14600

SO FROM HERE

X = 17000

so price Market price of jacket = 17000

Step-by-step explanation:


Answered by FelisFelis
35

Answer:

The marked price of jacket is 22000.

Step-by-step explanation:

Consider the provided information.

Let us consider the marked price of the jacket is Rs. x.

It is given that the marked price of pants is Rs. 8500 less than the marked price of the jacket. Therefore the marked price of pants is Rs x - 8500.

If there is 30% off on marked price, that means someone needs to pay 70% of the marked price.

If the marked price of the jacket is Rs. x. Then, someone needs to pay 70% of x. Which can be written as:

\frac{70}{100}\times x

0.7\times x=0.7x

If there is 40% off on marked price, that means someone needs to pay 60% of the marked price.

If the marked price of the pants is Rs. x - 8500 then, someone needs to pay 60% of x - 8500. Which can be written as:

\frac{60}{100}\times (x-8500)

0.6\times (x-8500)

The total sale price of both items is Rs. 23500, which can be written as:

0.7x + 0.6(x-8500) = 23500

0.7x + 0.6x-5100=23500

1.3x=23500+5100

1.3x=28600

x=22000

Therefore, the marked price of jacket is 22000.

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