Math, asked by QweenRani853, 2 days ago

A store owner sold 10  1/4 kg, 6  3/5 kg and 2  4/5 kg of sugar to three customers in a day. Find the total weight of sugar sold on that day?

Answers

Answered by rishupandey147
0

owner sold to first customer = 10 1/4= 41/4 kg

owner sold to second customer= 6 3/5= 33/5 kg

owner sold to third customer = 2 4/5 = 14/5 kg

total sugar sold = 41/4+33/5+14/5

= 41/4+47/5

=(41*5+47*4)/20

=393/20

19 13/20 kg

Similar questions